Surfstat.australia: an online text in introductory Statistics

STATISTICAL INFERENCE

STATISTICAL CONTROL CHARTS

Case 1: µ, s known

x-bar chart construction when the process has known standards µ and s.

The usual American and Japanese practice in making charts is to place the control limits at
µ ± , where

µ is the mean of the distribution of individual measurements on items produced by the process in its present state, it describes the centre or aim of the process;

s is the standard deviation of the process;

n is the size of the regular samples that are taken over time to produce the data.

The probability that a particular falls outside the µ ± limits when the process is in control is about 0.003, based on the assumption that we expect to have a distribution that is nearly normal. (Recall that the Central Limit Theorem suggests that the sample mean will be closer to normal than the individual measurements - approximate normality is good enough as the control chart provides only a warning that further investigation may be required.)

Example - Air conditioner thermostats

A maker of car air conditioners checks a sample of 4 thermostatic controls from each hour's production. The standard for the process mean is µ=75°. Past experience indicates that the response temperature of properly adjusted thermostats varies with s=0.5°. The mean response temperature for each hour's sample is plotted on an control chart. The centre line on the chart would be µ=75° and the control limits would be drawn at

= 74.25° and 75.75°

For known µ and s, an x-bar control chart for continuous data, constructed with subgroups size n, has

Centre line

CL = µ

Upper Control Limit

UCL = µ +

Lower Control Limit

LCL = µ -

To produce an x-bar control chart using Minitab, the command is

MTB> xbarchart c E;

SUBC> mu k1;

SUBC> sigma k2.

where c is the column containing the data, E is the sample size and k1 and k2 are the values of µ and s.

Case 2: µ, s not known

x-bar chart construction when process does not have known standards µ and s.

Example (continued) - Variation In Percent Solids

The team's first set of data is shown in the following table. To simplify the data, 60 has been subtracted from each observation.
Percent Solids (60 Subtracted) of Seventeen Samples in Triplicate
Subgroup
123456 789101112 1314151617
8.84.35.87.58.25.17.56.66.34.96.0 7.67.05.87.55.07.5
9.23.36.16.27.37.07.77.97.34.76.2 7.36.57.15.96.16.3
9.13.87.66.07.26.97.65.77.35.46.8 6.25.75.26.05.77.4
Average
9.033.806.506.577.576.337.606.736.97 5.006.337.036.406.036.475.607.07
Standard Deviation (s)
0.210.500.960.810.551.070.101.110.58 0.360.420.740.660.970.900.560.67
Range (R)
0.401.001.801.501.001.900.202.201.00 0.700.801.401.301.901.601.101.20

These data are used to estimate the process mean and standard deviation.

Just as we denote a mean by placing a bar over the top (), the average of the averages, or the grand sample mean, is denoted with a bar over the bar: .

The average of all of the observations is = 6.53; this is an estimate of the process mean µ (if the process is in control).

We can estimate the process standard deviation from the average of the standard deviations of the subgroups:

Again, we must assume the process is in control, at least with respect to its standard deviation, for this estimate to be meaningful. The estimate based on is not an unbiased estimate of the process standard deviation. Constants (usually referred to as c4) have been computed which yield an unbiased estimate of the process standard deviation, s, (at least for normally distributed data) given by /c4. The value of c4 for various subgroup sizes is shown below.


 n   2      3      4      5      6      7      8      9     10 

c4 .780 .886 .921 .940 .952 .959 .965 .969 .973

Since we obtained = 0.66, the unbiased estimate of process standard deviation is /c4, so = 0.66/0.886 = 0.74. The standard error of each subgroup mean is thus . The mean of the distribution of subgroup averages is the same as the mean of the distribution of single observations. Appealing to the Central Limit Theorem, for a stable process we should find about 99.7% of the subgroup averages within three standard errors of .


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